y^2=7/10

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Solution for y^2=7/10 equation:



y^2=7/10
We move all terms to the left:
y^2-(7/10)=0
We add all the numbers together, and all the variables
y^2-(+7/10)=0
We get rid of parentheses
y^2-7/10=0
We multiply all the terms by the denominator
y^2*10-7=0
Wy multiply elements
10y^2-7=0
a = 10; b = 0; c = -7;
Δ = b2-4ac
Δ = 02-4·10·(-7)
Δ = 280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{280}=\sqrt{4*70}=\sqrt{4}*\sqrt{70}=2\sqrt{70}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{70}}{2*10}=\frac{0-2\sqrt{70}}{20} =-\frac{2\sqrt{70}}{20} =-\frac{\sqrt{70}}{10} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{70}}{2*10}=\frac{0+2\sqrt{70}}{20} =\frac{2\sqrt{70}}{20} =\frac{\sqrt{70}}{10} $

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